199. Binary Tree Right Side View

BFS

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class Solution {
public List<Integer> rightSideView(TreeNode root) {
List<Integer> numList = new ArrayList<>();
Queue<TreeNode> queue = new LinkedList<>();
if (root != null) {
queue.offer(root);
}

while (!queue.isEmpty()) {
for (int i = queue.size(); i > 0; i--) {
TreeNode node = queue.poll();
if (i == 1) { // 注意此处是与 1 比较
numList.add(node.val);
}

if (node.left != null) {
queue.offer(node.left);
}
if (node.right != null) {
queue.offer(node.right);
}
}
}

return numList;
}
}

DFS

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class Solution {
public List<Integer> rightSideView(TreeNode root) {
List<Integer> numList = new ArrayList<>();
dfs(numList, root, 0);
return numList;
}

private void dfs(List<Integer> numList, TreeNode node, int depth) {
if (node == null) {
return;
}

if (numList.size() == depth) {
numList.add(node.val);
}
dfs(numList, node.right, depth + 1);
dfs(numList, node.left, depth + 1);
}
}

References

199. Binary Tree Right Side View
剑指 Offer II 046. 二叉树的右侧视图