面试题 01.09. 字符串轮转 Poison 2023-02-28 12345678910class Solution { public boolean isFlipedString(String s1, String s2) { if (s1.length() != s2.length()) { return false; } String concatenatedStr = s2 + s2; return concatenatedStr.contains(s1); }} References面试题 01.09. 字符串轮转