面试题 17.17. 多次搜索

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class Solution {
private static class TrieNode {
private final TrieNode[] children;
private String word;

public TrieNode() {
this.children = new TrieNode[26];
}
}

private static class Trie {
private final TrieNode root;

public Trie() {
this.root = new TrieNode();
}

public void insert(String word) {
TrieNode node = root;
for (int i = 0; i < word.length(); i++) {
int index = word.charAt(i) - 'a';
if (node.children[index] == null) {
// 注意仅为空时才需要创建新的 TrieNode, 否则会将之前已有的覆盖
node.children[index] = new TrieNode();
}
node = node.children[index];
}
node.word = word;
}

public List<String> search(String big) {
List<String> wordList = new ArrayList<>();
TrieNode node = root;
for (int i = 0; i < big.length(); i++) {
int index = big.charAt(i) - 'a';
node = node.children[index];
if (node == null) {
break;
}
if (node.word != null) {
wordList.add(node.word);
}
}

return wordList;
}
}

public int[][] multiSearch(String big, String[] smalls) {
// 使用 smalls 建树
Trie trie = new Trie();
for (String word : smalls) {
trie.insert(word);
}

Map<String, List<Integer>> wordToStartIndexMap = new HashMap<>();
for (int startIndex = 0; startIndex < big.length(); startIndex++) {
for (String word : trie.search(big.substring(startIndex))) {
wordToStartIndexMap.computeIfAbsent(word, k -> new ArrayList<>()).add(startIndex);
}
}

int[][] res = new int[smalls.length][];
for (int i = 0; i < smalls.length; i++) {
List<Integer> startIndexList = wordToStartIndexMap.getOrDefault(smalls[i], Collections.emptyList());
res[i] = new int[startIndexList.size()];
for (int j = 0; j < startIndexList.size(); j++) {
res[i][j] = startIndexList.get(j);
}
}
return res;
}
}

关键是使用 smalls 去建立 Trie 树。

References

面试题 17.17. 多次搜索