539. Minimum Time Difference

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class Solution {
public int findMinDifference(List<String> timePoints) {
List<Integer> minuteList = new ArrayList<>(timePoints.size());
for (String timePoint : timePoints) {
minuteList.add(getMinutes(timePoint));
}
Collections.sort(minuteList);

int minDiffMinutes = Math.min(minuteList.get(minuteList.size() - 1) - minuteList.get(0), minuteList.get(0) + 24 * 60 - minuteList.get(minuteList.size() - 1));
for (int i = 0; i < minuteList.size()-1; i++) {
minDiffMinutes = Math.min(minDiffMinutes, minuteList.get(i + 1) - minuteList.get(i));
}
return minDiffMinutes;
}

private Integer getMinutes(String timePoint) {
int hour = Integer.parseInt(timePoint.substring(0, 2));
int minute = Integer.parseInt(timePoint.substring(3));
return hour * 60 + minute;
}
}

References

539. Minimum Time Difference
剑指 Offer II 035. 最小时间差