1480. Running Sum of 1d Array

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class Solution {
public int[] runningSum(int[] nums) {
int[] prefixSums = new int[nums.length];
prefixSums[0] = nums[0];
for (int i = 1; i < nums.length; i++) {
prefixSums[i] = prefixSums[i - 1] + nums[i];
}
return prefixSums;
}
}

References

1480. Running Sum of 1d Array