1289. Minimum Falling Path Sum II

DP

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class Solution {
public int minFallingPathSum(int[][] grid) {
int n = grid.length;

for (int i = 1; i < n; i++) {
for (int j = 0; j < n; j++) {
int min = Integer.MAX_VALUE;
for (int k = 0; k < n; k++) {
if (k == j) {
continue;
}
min = Math.min(min, grid[i - 1][k]);
}

grid[i][j] += min;
}
}

int minPathSum = Integer.MAX_VALUE;
for (int j = 0; j < n; j++) {
minPathSum = Math.min(minPathSum, grid[n - 1][j]);
}
return minPathSum;
}
}

DP

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class Solution {
public int minFallingPathSum(int[][] grid) {
int n = grid.length;

int firstMinIndex = -1, secondMinIndex = -1;
for (int j = 0; j < n; j++) {
int num = grid[0][j];
if (num < (firstMinIndex == -1 ? Integer.MAX_VALUE : grid[0][firstMinIndex])) {
secondMinIndex = firstMinIndex;
firstMinIndex = j;
} else if (num < (secondMinIndex == -1 ? Integer.MAX_VALUE : grid[0][secondMinIndex])) {
secondMinIndex = j;
}
}

for (int i = 1; i < n; i++) {
int tempFirstMinIndex = -1, tempSecondMinIndex = -1;
for (int j = 0; j < n; j++) {
if (j == firstMinIndex) {
grid[i][j] += grid[i - 1][secondMinIndex];
} else {
grid[i][j] += grid[i - 1][firstMinIndex];
}

int num = grid[i][j];
if (num < (tempFirstMinIndex == -1 ? Integer.MAX_VALUE : grid[i][tempFirstMinIndex])) {
tempSecondMinIndex = tempFirstMinIndex;
tempFirstMinIndex = j;
} else if (num < (tempSecondMinIndex == -1 ? Integer.MAX_VALUE : grid[i][tempSecondMinIndex])) {
tempSecondMinIndex = j;
}
}

firstMinIndex = tempFirstMinIndex;
secondMinIndex = tempSecondMinIndex;
}

int minPathSum = Integer.MAX_VALUE;
for (int j = 0; j < n; j++) {
minPathSum = Math.min(minPathSum, grid[n - 1][j]);
}
return minPathSum;
}
}

References

1289. Minimum Falling Path Sum II