313. Super Ugly Number

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class Solution {
public int nthSuperUglyNumber(int n, int[] primes) {
int[] dp = new int[n];
dp[0] = 1;

int[] points = new int[primes.length];
for (int i = 1; i < dp.length; i++) {
int min = Integer.MAX_VALUE;
for (int j = 0; j < primes.length; j++) {
if (dp[points[j]] <= Integer.MAX_VALUE / primes[j]) {
min = Math.min(min, dp[points[j]] * primes[j]);
}
}
for (int j = 0; j < points.length; j++) {
if (dp[points[j]] <= Integer.MAX_VALUE / primes[j]) {
if (min == dp[points[j]] * primes[j]) {
points[j]++;
}
}
}
dp[i] = min;
}

return dp[n - 1];
}
}

References

313. Super Ugly Number